C# by Patrik

Generate a Random Integers

The following example demonstrates how to generate a random integer.

 Random random = new Random();
int num = random.Next();

Call the Next() method multiple times to get the multiple random numbers, as shown below.

 Random random = new Random();
 
for (int i = 0; i < 4; i++)
{
    Console.WriteLine(random.Next());
}

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	Random random = new Random();

	for (int i = 0; i < 4; i++)
	{
	Console.WriteLine(random.Next());
	}